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1 | static <A> S stringTrie_longestPrefix_loose(StringTrie<A> trie, S string) { |
2 | int n = 0; |
3 | S s = string; |
4 | while licensed { |
5 | if (trie == null) break; |
6 | if (empty(string)) break; |
7 | S prefix = trie.longestLocalPrefix(s); |
8 | if (empty(prefix)) break; |
9 | n += l(prefix); |
10 | trie = trie.getChild(prefix); |
11 | s = dropFirst(s, l(prefix)); |
12 | } |
13 | ret takeFirst(n, string); |
14 | } |
Began life as a copy of #1030182
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Snippet ID: | #1030183 |
Snippet name: | stringTrie_longestPrefix_loose - longest common prefix of string and trie elements |
Eternal ID of this version: | #1030183/1 |
Text MD5: | 46f6d425cdc885c217d96fdb342cf636 |
Transpilation MD5: | 70a612b366402e5c192c6830053a9fdc |
Author: | stefan |
Category: | javax / tries |
Type: | JavaX fragment (include) |
Public (visible to everyone): | Yes |
Archived (hidden from active list): | No |
Created/modified: | 2020-11-12 14:25:30 |
Source code size: | 389 bytes / 14 lines |
Pitched / IR pitched: | No / No |
Views / Downloads: | 181 / 260 |
Referenced in: | [show references] |