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// return longest common prefix of s an an entry of set sS longestCommonPrefixOfNavigableSetAndString(S s, NavigableSet<S> set) { if (set == null || s == null) null; S a = set.floor(s), b = set.higher(s); int n1 = lCommonPrefix(a, s), n2 = lCommonPrefix(b, s); ifdef longestCommonPrefixOfNavigableSetAndString_debug printVars_str("longestCommonPrefixOfNavigableSetAndString", +s, +set, +n1, +n2); endifdef int n = Math.max(n1, n2); ret takeFirst_string(s, n); }
Began life as a copy of #1029748
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Snippet ID: | #1030164 |
Snippet name: | longestCommonPrefixOfNavigableSetAndString [OK] |
Eternal ID of this version: | #1030164/8 |
Text MD5: | d591ee2215834ceee19b62d3d350b09a |
Author: | stefan |
Category: | javax |
Type: | JavaX fragment (include) |
Public (visible to everyone): | Yes |
Archived (hidden from active list): | No |
Created/modified: | 2020-11-12 10:50:13 |
Source code size: | 489 bytes / 11 lines |
Pitched / IR pitched: | No / No |
Views / Downloads: | 211 / 306 |
Version history: | 7 change(s) |
Referenced in: | [show references] |