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1 | static L<Int> sqrt2progression_int(int n, double startValue) {
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2 | L<Int> l = emptyList(n); |
3 | double x = startValue; |
4 | for i to n: {
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5 | l.add(iround(x)); |
6 | x /= sqrt(2); |
7 | } |
8 | ret l; |
9 | } |
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| Snippet ID: | #1027283 |
| Snippet name: | sqrt2progression_int (divide by sqrt(2) repeatedly) |
| Eternal ID of this version: | #1027283/3 |
| Text MD5: | 49a21a5904d9ad0cb3a2dd8017bd064e |
| Transpilation MD5: | bedf2b4fcbe6974ad86e5a3df3439ba3 |
| Author: | stefan |
| Category: | javax / maths |
| Type: | JavaX fragment (include) |
| Public (visible to everyone): | Yes |
| Archived (hidden from active list): | No |
| Created/modified: | 2020-02-29 16:42:30 |
| Source code size: | 193 bytes / 9 lines |
| Pitched / IR pitched: | No / No |
| Views / Downloads: | 168 / 261 |
| Version history: | 2 change(s) |
| Referenced in: | [show references] |