1 | // o is either a map already (string->object) or an arbitrary object, |
2 | // in which case its fields are converted into a map. |
3 | static Map<S, O> objectToMap_inOrder_withoutFields(O o, Collection<S> withoutFields) { |
4 | if (o == null) null; |
5 | if (o instanceof Map) ret (Map) o; |
6 | new LinkedHashMap<S, O> map; |
7 | for (S field : listWithoutSet(fieldsInOrder(o), withoutFields)) |
8 | map.put(field, get(o, field)); |
9 | ret map; |
10 | } |
Began life as a copy of #1019760
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Snippet ID: | #1021414 |
Snippet name: | objectToMap_inOrder_withoutFields |
Eternal ID of this version: | #1021414/1 |
Text MD5: | 42f13a04ae14a2d64b6de71d3acc0d21 |
Author: | stefan |
Category: | javax |
Type: | JavaX fragment (include) |
Public (visible to everyone): | Yes |
Archived (hidden from active list): | No |
Created/modified: | 2019-02-10 23:41:57 |
Source code size: | 424 bytes / 10 lines |
Pitched / IR pitched: | No / No |
Views / Downloads: | 359 / 387 |
Referenced in: | [show references] |