1 | // o is either a map already (string->object) or an arbitrary object, |
2 | // in which case its fields are converted into a map. |
3 | static Map<S, O> objectToMap_inOrder(O o) {
|
4 | if (o == null) null; |
5 | if (o instanceof Map) ret (Map) o; |
6 | new LinkedHashMap<S, O> map; |
7 | for (S field : fieldsInOrder(o)) |
8 | map.put(field, get(o, field)); |
9 | ret map; |
10 | } |
Began life as a copy of #1002179
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| Snippet ID: | #1019760 |
| Snippet name: | objectToMap_inOrder |
| Eternal ID of this version: | #1019760/1 |
| Text MD5: | 2d7560d25ee4482114e8d61f3c4cbef8 |
| Author: | stefan |
| Category: | javax |
| Type: | JavaX fragment (include) |
| Public (visible to everyone): | Yes |
| Archived (hidden from active list): | No |
| Created/modified: | 2018-11-25 02:24:33 |
| Source code size: | 350 bytes / 10 lines |
| Pitched / IR pitched: | No / No |
| Views / Downloads: | 315 / 333 |
| Referenced in: | [show references] |