// is it "* *" etc. (SNL juxtaposition), or "[]" (NL juxtaposition)? static boolean isJuxta(Lisp l) { if (l == null) ret false; if (l.is("[]")) ret true; if (l(l.head) == 0) ret false; for (int i = 0; i < l(l.head); i++) if (l.head.charAt(i) != ((i & 1) == 0 ? '*' : ' ')) ret false; ret true; }
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Travelled to 13 computer(s): aoiabmzegqzx, bhatertpkbcr, cbybwowwnfue, cfunsshuasjs, gwrvuhgaqvyk, ishqpsrjomds, lpdgvwnxivlt, mqqgnosmbjvj, pyentgdyhuwx, pzhvpgtvlbxg, tslmcundralx, tvejysmllsmz, vouqrxazstgt
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Snippet ID: | #1002747 |
Snippet name: | isJuxta |
Eternal ID of this version: | #1002747/1 |
Text MD5: | d8c6f3b02c5e93638061520003b49e51 |
Author: | stefan |
Category: | snl logic |
Type: | JavaX fragment (include) |
Public (visible to everyone): | Yes |
Archived (hidden from active list): | No |
Created/modified: | 2016-03-03 02:10:18 |
Source code size: | 324 bytes / 10 lines |
Pitched / IR pitched: | No / No |
Views / Downloads: | 752 / 862 |
Referenced in: | #1006654 - Standard functions list 2 (LIVE, continuation of #761) #3000382 - Answer for ferdie (>> t = 1, f = 0) #3000383 - Answer for funkoverflow (>> t=1, f=0 okay) |