static S collapseWord(S s) { if (s == null) ret ""; new StringBuilder buf; for (int i = 0; i < l(s); i++) if (i == 0 || !charactersEqualIC(s.charAt(i), s.charAt(i-1))) buf.append(s.charAt(i)); ret buf.toString(); }
download show line numbers debug dex old transpilations
Travelled to 15 computer(s): aoiabmzegqzx, bhatertpkbcr, cbybwowwnfue, cfunsshuasjs, ekrmjmnbrukm, gwrvuhgaqvyk, ishqpsrjomds, lpdgvwnxivlt, mqqgnosmbjvj, pyentgdyhuwx, pzhvpgtvlbxg, tslmcundralx, tvejysmllsmz, vouqrxazstgt, whxojlpjdney
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Snippet ID: | #1001929 |
Snippet name: | collapseWord - remove next-to-each-other duplicate/repeating characters from word; now IC |
Eternal ID of this version: | #1001929/8 |
Text MD5: | b4df1c8e86da66e56d273e5b1d1c8922 |
Author: | stefan |
Category: | |
Type: | JavaX fragment (include) |
Public (visible to everyone): | Yes |
Archived (hidden from active list): | No |
Created/modified: | 2017-10-11 18:11:05 |
Source code size: | 239 bytes / 8 lines |
Pitched / IR pitched: | No / No |
Views / Downloads: | 683 / 1367 |
Version history: | 7 change(s) |
Referenced in: | #1002427 - Accellerating 629 (SPIKE) #1006654 - Standard functions list 2 (LIVE, continuation of #761) #1011014 - maxRunlengthOfRepeatingChars #3000382 - Answer for ferdie (>> t = 1, f = 0) #3000383 - Answer for funkoverflow (>> t=1, f=0 okay) |