import java.util.*; import java.util.zip.*; import java.util.List; import java.util.regex.*; import java.util.concurrent.*; import java.util.concurrent.atomic.*; import java.util.concurrent.locks.*; import javax.swing.*; import javax.swing.event.*; import javax.swing.text.*; import javax.swing.table.*; import java.io.*; import java.net.*; import java.lang.reflect.*; import java.lang.ref.*; import java.lang.management.*; import java.security.*; import java.security.spec.*; import java.awt.*; import java.awt.event.*; import java.awt.image.*; import javax.imageio.*; import java.math.*; class main { // This code has been contributed by 29AjayKumar // from: https://www.geeksforgeeks.org/timsort/ static final int timSortIntArray_RUN = 32; // this function sorts array from left index to // to right index which is of size atmost RUN static void timSortIntArray_insertionSort(int[] arr, int left, int right) { for (int i = left + 1; i <= right; i++) { int temp = arr[i]; int j = i - 1; while (j >= left && arr[j] > temp) { arr[j + 1] = arr[j]; j--; } arr[j + 1] = temp; } } // merge function merges the sorted runs static void timSortIntArray_merge(int[] arr, int l, int m, int r) { // original array is broken in two parts // left and right array int len1 = m - l + 1, len2 = r - m; int[] left = new int[len1]; int[] right = new int[len2]; for (int x = 0; x < len1; x++) { left[x] = arr[l + x]; } for (int x = 0; x < len2; x++) { right[x] = arr[m + 1 + x]; } int i = 0; int j = 0; int k = l; // after comparing, we merge those two array // in larger sub array while (i < len1 && j < len2) { if (left[i] <= right[j]) { arr[k] = left[i]; i++; } else { arr[k] = right[j]; j++; } k++; } // copy remaining elements of left, if any while (i < len1) { arr[k] = left[i]; k++; i++; } // copy remaining element of right, if any while (j < len2) { arr[k] = right[j]; k++; j++; } } // iterative Timsort function to sort the // array[0...n-1] (similar to merge sort) static void timSortIntArray(int[] arr) { timSortIntArray(arr, lIntArray(arr)); } static void timSortIntArray(int[] arr, int n) { // Sort individual subarrays of size RUN for (int i = 0; i < n; i += timSortIntArray_RUN) { timSortIntArray_insertionSort(arr, i, Math.min((i + 31), (n - 1))); } // start merging from size RUN (or 32). It will merge // to form size 64, then 128, 256 and so on .... for (int size = timSortIntArray_RUN; size < n; size = 2 * size) { // pick starting point of left sub array. We // are going to merge arr[left..left+size-1] // and arr[left+size, left+2*size-1] // After every merge, we increase left by 2*size for (int left = 0; left < n; left += 2 * size) { // find ending point of left sub array // mid+1 is starting point of right sub array int mid = min(left + size - 1, n - 1); int right = Math.min(left + 2 * size - 1, n - 1); //if (right < mid || mid < left) fail("Overflow at " + n2(left) + "/" + size + ". mid=" + n2(mid) + ", right=" + n2(right)); // merge sub array arr[left.....mid] & // arr[mid+1....right] timSortIntArray_merge(arr, left, mid, right); } } } static int lIntArray(int[] a) { return a == null ? 0 : a.length; } static int min(int a, int b) { return Math.min(a, b); } static long min(long a, long b) { return Math.min(a, b); } static float min(float a, float b) { return Math.min(a, b); } static float min(float a, float b, float c) { return min(min(a, b), c); } static double min(double a, double b) { return Math.min(a, b); } static double min(double[] c) { double x = Double.MAX_VALUE; for (double d : c) x = Math.min(x, d); return x; } static float min(float[] c) { float x = Float.MAX_VALUE; for (float d : c) x = Math.min(x, d); return x; } static byte min(byte[] c) { byte x = 127; for (byte d : c) if (d < x) x = d; return x; } static short min(short[] c) { short x = 0x7FFF; for (short d : c) if (d < x) x = d; return x; } static int min(int[] c) { int x = Integer.MAX_VALUE; for (int d : c) if (d < x) x = d; return x; } }