-- a, b are the last 2 words
pairs = {}
text = {}
ntext = 0
word = {}
wordIdx = {}
function p(m, s)
  if s ~= nil then
    for i = 1, s:len() do
      local c = s:sub(i, i)
      ntext = ntext+1
      text[ntext] = c
      if c >= "a" and c <= "z" or c >= "A" and c <= "Z" then
        nword = nword+1
        word[nword] = c
      else
        if nword ~= 0 then
          newWord(table.concat(word))
          word = {}
          nword = 0
        end
      end
    end
  end

  local x = wordIdx[b]
  if x ~= nil then return table.concat(text, "", x,
    math.min(ntext, x+math.min(100, m)-1)) end
    
end

function newWord(w)
  a = b
  b = w
  wordIdx[b] = ntext+1
end