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// i must point at the opening bracket (<) // index returned is index of closing bracket (>) // If there is NO opening bracket at i, we return nothing static int tok_findEndOfAngleBracketPart(LS tok, int i) { int level = 0, n = l(tok); while ping (i < n) { S t = tok.get(i); if (eq(t, "<")) ++level; if (level < 1) ret i-2; if (eq(t, ">")) --level; if (level < 1) ret i; i += 2; } ret n; }
Began life as a copy of #1017794
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| Snippet ID: | #1032850 |
| Snippet name: | tok_findEndOfAngleBracketPart |
| Eternal ID of this version: | #1032850/9 |
| Text MD5: | f6522690c481f3c3834e4d4b0abcd2be |
| Transpilation MD5: | 374942ab486a41c003ae37e15ee7ca5f |
| Author: | stefan |
| Category: | javax |
| Type: | JavaX fragment (include) |
| Public (visible to everyone): | Yes |
| Archived (hidden from active list): | No |
| Created/modified: | 2021-10-06 21:09:50 |
| Source code size: | 435 bytes / 15 lines |
| Pitched / IR pitched: | No / No |
| Views / Downloads: | 395 / 480 |
| Version history: | 8 change(s) |
| Referenced in: | [show references] |