takeFirst_clone function (take first n elements of a list, always make a new list) [1022354]

14
LINES

< > BotCompany Repo | #1022354 // takeFirst_clone function (take first n elements of a list, always make a new list)

JavaX fragment (include)

static <A> L<A> takeFirst_clone(L<A> l, int n) {
  ret cloneSubList(l, 0, n);
}

static <A> L<A> takeFirst_clone(int n, L<A> l) {
  ret takeFirst_clone(l, n);
}

static <A> L<A> takeFirst_clone(int n, Iterable<A> i) {
  L l = new L;
  Iterator<A> it = i.iterator();
  repeat n { if (it.hasNext()) l.add(it.next()); else break; }
  ret l;
}

Author comment

Began life as a copy of #1007549

download show line numbers debug dex old transpilations

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Snippet ID:	#1022354
Snippet name:	takeFirst_clone function (take first n elements of a list, always make a new list)
Eternal ID of this version:	#1022354/3
Text MD5:	776f0fe8882e3688ea61f36a57a557c9
Author:	stefan
Category:	javax
Type:	JavaX fragment (include)
Public (visible to everyone):	Yes
Archived (hidden from active list):	No
Created/modified:	2019-03-15 09:13:25
Source code size:	354 bytes / 14 lines
Pitched / IR pitched:	No / No
Views / Downloads:	540 / 561
Version history:	2 change(s)
Referenced in:	[show references]

1	static <A> L<A> takeFirst_clone(L<A> l, int n) {
2	ret cloneSubList(l, 0, n);
3	}
4
5	static <A> L<A> takeFirst_clone(int n, L<A> l) {
6	ret takeFirst_clone(l, n);
7	}
8
9	static <A> L<A> takeFirst_clone(int n, Iterable<A> i) {
10	L l = new L;
11	Iterator<A> it = i.iterator();
12	repeat n { if (it.hasNext()) l.add(it.next()); else break; }
13	ret l;
14	}