Look for prefix in TreeSet pure java spike [1022124]

< > BotCompany Repo | #1022124 // Look for prefix in TreeSet pure java spike

JavaX source code (desktop) [tags: use-pretranspiled] - run with: x30.jar

!7

p {
  new TreeSet<S> set;
  set.add("pot");
  set.add("potash");
  System.out.println(containsPrefixOf(set, "pot"));
}

sbool containsPrefixOf(TreeSet<S> set, S s) {
  if (set == null || s == null) false;
  while true {
    S key = set.floor(s);
    
    if (key == null) false; // s is in front of whole set => no prefix in there
    int n = lengthOfCommonPrefix(key, s);
    if (n == key.length()) return true; // found!
    s = s.substring(0, n); // shorten and try again
  }
}

static int lengthOfCommonPrefix(String a, String b) {
  int i = 0, n = Math.min(a.length(), b.length());
  while (i < n && a.charAt(i) == b.charAt(i))
    ++i;
  return i;
}

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Snippet ID:

#1022124

Snippet name:

Look for prefix in TreeSet pure java spike

Eternal ID of this version:

#1022124/2

Text MD5:

0acd14dcec17b7efbf09826a5af4ff27

Transpilation MD5:

4bcf7e403c6b79b7bc1344d20f8ee101

Author:

stefan

Category:

javax

Type:

JavaX source code (desktop)

Public (visible to everyone):

Yes

Archived (hidden from active list):

Created/modified:

2019-03-08 00:08:34

Source code size:

687 bytes / 27 lines

Pitched / IR pitched:

No / No

Views / Downloads:

636 / 1510

Version history:

1 change(s)

Referenced in:

[show references]

1	!7
2
3	p {
4	new TreeSet<S> set;
5	set.add("pot");
6	set.add("potash");
7	System.out.println(containsPrefixOf(set, "pot"));
8	}
9
10	sbool containsPrefixOf(TreeSet<S> set, S s) {
11	if (set == null \|\| s == null) false;
12	while true {
13	S key = set.floor(s);
14
15	if (key == null) false; // s is in front of whole set => no prefix in there
16	int n = lengthOfCommonPrefix(key, s);
17	if (n == key.length()) return true; // found!
18	s = s.substring(0, n); // shorten and try again
19	}
20	}
21
22	static int lengthOfCommonPrefix(String a, String b) {
23	int i = 0, n = Math.min(a.length(), b.length());
24	while (i < n && a.charAt(i) == b.charAt(i))
25	++i;
26	return i;
27	}