static <A> A nextToLastThat(L<A> l, O pred) { int found = 0; for (int i = l(l)-1; i >= 0; i--) { A a = l.get(i); if (checkCondition(pred, a)) if (++found >= 2) ret a; } null; } static <A> A mapLike nextToLastThat(O pred, L<A> l) { ret nextToLastThat(l, pred); }
Began life as a copy of #1021565
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Travelled to 7 computer(s): bhatertpkbcr, cfunsshuasjs, mqqgnosmbjvj, pyentgdyhuwx, pzhvpgtvlbxg, tvejysmllsmz, vouqrxazstgt
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| Snippet ID: | #1022066 |
| Snippet name: | nextToLastThat - find next to last element in list that matches a predicate |
| Eternal ID of this version: | #1022066/1 |
| Text MD5: | a64fe43272be8cf5a90c226569b623ed |
| Author: | stefan |
| Category: | javax |
| Type: | JavaX fragment (include) |
| Public (visible to everyone): | Yes |
| Archived (hidden from active list): | No |
| Created/modified: | 2019-03-06 08:39:35 |
| Source code size: | 307 bytes / 14 lines |
| Pitched / IR pitched: | No / No |
| Views / Downloads: | 439 / 497 |
| Referenced in: | [show references] |