static LPair<S> directlyAdjacentWords(S s) { LS tok = javaTokC(s); LPair<S> out = new L; for (int i = 0; i+1 < l(tok); i++) if (isIdentifier(tok.get(i)) && isIdentifier(tok.get(i+1))) out.add(pair(tok.get(i), tok.get(i+1))); ret out; }
download show line numbers debug dex old transpilations
Travelled to 13 computer(s): aoiabmzegqzx, bhatertpkbcr, cbybwowwnfue, cfunsshuasjs, gwrvuhgaqvyk, irmadwmeruwu, ishqpsrjomds, lpdgvwnxivlt, mqqgnosmbjvj, pyentgdyhuwx, pzhvpgtvlbxg, tvejysmllsmz, vouqrxazstgt
No comments. add comment
| Snippet ID: | #1018886 |
| Snippet name: | directlyAdjacentWords - no punctuation between them |
| Eternal ID of this version: | #1018886/3 |
| Text MD5: | 7b702ff73b8902b2d9313f0bf62fd314 |
| Author: | stefan |
| Category: | javax / a.i. |
| Type: | JavaX fragment (include) |
| Public (visible to everyone): | Yes |
| Archived (hidden from active list): | No |
| Created/modified: | 2018-10-15 15:16:22 |
| Source code size: | 260 bytes / 8 lines |
| Pitched / IR pitched: | No / No |
| Views / Downloads: | 245 / 297 |
| Version history: | 2 change(s) |
| Referenced in: | [show references] |