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< > BotCompany Repo | #1002036 // Huge English Dictionary Bot

JavaX source code [tags: use-pretranspiled] - run with: x30.jar

Libraryless. Click here for Pure Java version (6187L/43K/143K).

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!7
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static CondensedStrings2 words;
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p {
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  File zip = loadLibrary("#1002028"); // words.zip
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  byte[] data = loadBinaryFromZip(zip, "words.txt");
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  S text = fromUTF8(data);
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  //print("UTF expansion: " + (l(data)-l(text))); // if 0, then strings can be extra-condensed.
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  data = null;
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  L<S> lines = toLines(text);
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  //print("Sorted? " + yn(isSortedList(lines)));
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  //print("Percentage sorted: " + formatDouble(percentageSorted(lines), 3));
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  //print("Unsorted indexes: " + struct(unsortedIndexes(lines)));
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  time { sort(lines); }
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  //print("Unsorted indexes: " + struct(unsortedIndexes(lines)));
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  text = null;
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  words = new CondensedStrings2(lines);
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  print(l(words) + " words loaded!");
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  //printMemoryInfo();
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  makeBot();
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}
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answer {
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  if (match("random english words", s))
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    ret randomWords(10);
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  if (match("* random english words", s, m))
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    ret randomWords(parseInt(m.get(0)));
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  if (match("1 random english word", s) || match("random english word", s))
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    ret randomWords(1);
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  if (match("how many english words do you know?", s, m))
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    ret format("I know * english words. Even funny ones such as ", words.size()) + quote(randomWord());
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  if (match("is * an english word?", s, m))
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    ret isWordQuick(m.unq(0)) ? " Yes." : "Not in my dictionary...";
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  if "English words *-*" {
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    int i = parseInt(m.unq(0));
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    int j = parseInt(m.unq(1));
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    ret structure(subList(words, i-1, min(i+50, j-1)));
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  }
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  if "number of characters in english dictionary"
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    ret str(words.totalSize());
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  if "number of different characters in english dictionary"
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    ret str(countDifferentChars());
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}
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static int countDifferentChars() {
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  new HashSet<Character> chars;
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  for (S s : words)
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    for (int i = 0; i < l(s); i++)
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      chars.add(s.charAt(i));
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  ret l(chars);
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}
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static S randomWord() {
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  ret words.get(random(words.size()));
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}
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static S randomWords(int n) {
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  n = min(n, 100);
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  new L<S> l;
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  for (int i = 0; i < n; i++)
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    l.add(randomWord());
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  ret join(" ", l) + (random(2) == 0 ? "?" : "!");
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}
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static bool isWord(S word) {
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  ret words.contains(toLower(word));
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}
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// assumes list is sorted (which we did)
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static bool isWordQuick(S word) {
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  word = toLower(word);
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  int i = Collections.binarySearch(words, word);
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  ret i >= 0;
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}

Author comment

Began life as a copy of #1002030

download  show line numbers  debug dex  old transpilations   

Travelled to 16 computer(s): aoiabmzegqzx, bhatertpkbcr, cbybwowwnfue, cfunsshuasjs, ddnzoavkxhuk, gwrvuhgaqvyk, ishqpsrjomds, jtubtzbbkimh, lpdgvwnxivlt, mqqgnosmbjvj, onxytkatvevr, pyentgdyhuwx, pzhvpgtvlbxg, tslmcundralx, tvejysmllsmz, vouqrxazstgt

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Snippet ID: #1002036
Snippet name: Huge English Dictionary Bot
Eternal ID of this version: #1002036/5
Text MD5: b7a3a86c5cac3c707232cc111019983d
Transpilation MD5: f3020440daa182822668ef3180f0abbc
Author: stefan
Category:
Type: JavaX source code
Public (visible to everyone): Yes
Archived (hidden from active list): No
Created/modified: 2018-04-07 14:59:29
Source code size: 2309 bytes / 75 lines
Pitched / IR pitched: No / No
Views / Downloads: 737 / 2471
Version history: 4 change(s)
Referenced in: [show references]