ln dropeveryother {
  boolean b;
  io(L in, L out) {
    if (!in.isEmpty())
      b = in[0] == out[0];
  }
  i(L in) {
    new L out;
    for (int i = b ? 0 : 1; i < #in; i += 2)
      out.add(in[i]);
    ret out;
  }
}Typed on the tablet - that's why it's so short! But why not always program this way? We just need an expander (translator).
download show line numbers debug dex old transpilations
Travelled to 13 computer(s): aoiabmzegqzx, bhatertpkbcr, cbybwowwnfue, cfunsshuasjs, gwrvuhgaqvyk, ishqpsrjomds, lpdgvwnxivlt, mqqgnosmbjvj, pyentgdyhuwx, pzhvpgtvlbxg, tslmcundralx, tvejysmllsmz, vouqrxazstgt
2 comment(s) hidden. show
| Snippet ID: | #1000489 | 
| Snippet name: | Drop every other (learner) | 
| Eternal ID of this version: | #1000489/1 | 
| Text MD5: | 58143651f8040a1adcec87dc0df28caf | 
| Author: | stefan | 
| Category: | |
| Type: | JavaX fragment (include) | 
| Public (visible to everyone): | Yes | 
| Archived (hidden from active list): | No | 
| Created/modified: | 2015-08-09 16:25:15 | 
| Source code size: | 235 bytes / 15 lines | 
| Pitched / IR pitched: | No / Yes | 
| Views / Downloads: | 1270 / 1208 | 
| Referenced in: | [show references] |