// from https://www.geeksforgeeks.org/convex-hull-using-jarvis-algorithm-or-wrapping/

sclass ConvexHull2D {
  Pt points;
    // To find orientation of ordered triplet (p, q, r).
    // The function returns following values
    // 0 --> p, q and r are collinear
    // 1 --> Clockwise
    // 2 --> Counterclockwise
    int orientation(Point p, Point q, Point r)
    {
        int val = (q.y - p.y) * (r.x - q.x) -
                  (q.x - p.x) * (r.y - q.y);
       
        if (val == 0) return 0;  // collinear
        return (val > 0)? 1: 2; // clock or counterclock wise
    }
      
    // Prints convex hull of a set of n points.
    Point points[], int n)
    {
        // There must be at least 3 points
        if (n < 3) return;
       
        // Initialize Result
        Vector<Point> hull = new Vector<Point>();
       
        // Find the leftmost point
        int l = 0;
        for (int i = 1; i < n; i++)
            if (points[i].x < points[l].x)
                l = i;
       
        // Start from leftmost point, keep moving 
        // counterclockwise until reach the start point
        // again. This loop runs O(h) times where h is
        // number of points in result or output.
        int p = l, q;
        do
        {
            // Add current point to result
            hull.add(points[p]);
       
            // Search for a point 'q' such that 
            // orientation(p, q, x) is counterclockwise 
            // for all points 'x'. The idea is to keep 
            // track of last visited most counterclock-
            // wise point in q. If any point 'i' is more 
            // counterclock-wise than q, then update q.
            q = (p + 1) % n;
              
            for (int i = 0; i < n; i++)
            {
               // If i is more counterclockwise than 
               // current q, then update q
               if (orientation(points[p], points[i], points[q])
                                                   == 2)
                   q = i;
            }
       
            // Now q is the most counterclockwise with
            // respect to p. Set p as q for next iteration, 
            // so that q is added to result 'hull'
            p = q;
       
        } while (p != l);  // While we don't come to first 
                           // point
       
        // Print Result
        for (Point temp : hull)
            System.out.println("(" + temp.x + ", " +
                                temp.y + ")");
    }