!747

m {
  p {
    L<S> list = litlist("a", "b", "a", "b");
    L<S> sublist = list.subList(2, 4);
    
    // Note that we couldn't find this out without the magic trick
    // (comparison by elements would yield 0 instead of 2).
    print("Index (should be 2): " + magicIndexOfSubList(list, sublist));
  }
}